Since Grisha behaved well last year, at New Year's Eve he was visited by Ded Moroz who brought an enormous bag of gifts with him! The bag contains n sweet candies from the good ol' bakery, each labeled from 1 to n corresponding to its tastiness. No two candies have the same tastiness.

The choice of candies has a direct effect on Grisha's happiness. One can assume that he should take the tastiest ones — but no, the holiday magic turns things upside down. It is the xor-sum of tastinesses that matters, not the ordinary sum!

A xor-sum of a sequence of integers a_1, a_2, ..., a_{m} is defined as the bitwise XOR of all its elements: $a_{1} \oplus a_{2} \oplus \ldots \oplus a_{m}$, here $\oplus$ denotes the bitwise XOR operation; more about bitwise XOR can be found here.

Ded Moroz warned Grisha he has more houses to visit, so Grisha can take no more than k candies from the bag. Help Grisha determine the largest xor-sum (largest xor-sum means maximum happiness!) he can obtain.

-----Input-----

The sole string contains two integers n and k (1 ≤ k ≤ n ≤ 10^18).

-----Output-----

Output one number — the largest possible xor-sum.

-----Examples-----

Input 4 3

Output 7

Input 6 6

Output 7

-----Note-----

In the first sample case, one optimal answer is 1, 2 and 4, giving the xor-sum of 7.

In the second sample case, one can, for example, take all six candies and obtain the xor-sum of 7.