Reziba has many magic gems. Each magic gem can be split into $M$ normal gems. The amount of space each magic (and normal) gem takes is $1$ unit. A normal gem cannot be split.

Reziba wants to choose a set of magic gems and split some of them, so the total space occupied by the resulting set of gems is $N$ units. If a magic gem is chosen and split, it takes $M$ units of space (since it is split into $M$ gems); if a magic gem is not split, it takes $1$ unit.

How many different configurations of the resulting set of gems can Reziba have, such that the total amount of space taken is $N$ units? Print the answer modulo $1000000007$ ($10^9+7$). Two configurations are considered different if the number of magic gems Reziba takes to form them differs, or the indices of gems Reziba has to split differ.

-----Input-----

The input contains a single line consisting of $2$ integers $N$ and $M$ ($1 \le N \le 10^{18}$, $2 \le M \le 100$).

-----Output-----

Print one integer, the total number of configurations of the resulting set of gems, given that the total amount of space taken is $N$ units. Print the answer modulo $1000000007$ ($10^9+7$).

-----Examples-----

Input 4 2

Output 5

Input 3 2

Output 3

-----Note-----

In the first example each magic gem can split into $2$ normal gems, and we know that the total amount of gems are $4$.

Let $1$ denote a magic gem, and $0$ denote a normal gem.

The total configurations you can have is: $1 1 1 1$ (None of the gems split); $0 0 1 1$ (First magic gem splits into $2$ normal gems); $1 0 0 1$ (Second magic gem splits into $2$ normal gems); $1 1 0 0$ (Third magic gem splits into $2$ normal gems); $0 0 0 0$ (First and second magic gems split into total $4$ normal gems).

Hence, answer is $5$.