Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture: $\left. \begin{array}{|r|r|r|r|r|r|} \hline & {2} & {9} & {16} & {23} & {30} \ \hline & {3} & {10} & {17} & {24} & {31} \ \hline & {4} & {11} & {18} & {25} & {} \ \hline & {5} & {12} & {19} & {26} & {} \ \hline & {6} & {13} & {20} & {27} & {} \ \hline & {7} & {14} & {21} & {28} & {} \ \hline 1 & {8} & {15} & {22} & {29} & {} \ \hline \end{array} \right.$

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

-----Input-----

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

-----Output-----

Print single integer: the number of columns the table should have.

-----Examples-----

Input 1 7

Output 6

Input 1 1

Output 5

Input 11 6

Output 5

-----Note-----

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.